.QUES. 6: Case 2:
Uncompensated Laboratory Results: pH =7.1, pCO2 = 42, HCO3-
a. List the condition - acidosis or alkalosis, metabolic
or respiratory, compensated or uncompensated.
pH =7.1 = acidosis, uncompensated
pCO2 = 42 = metabolic, uncompensated
HCO3- = 12 = metabolic
b. What is the primary cause of the condition?
Could be deficit of bicarbonate caused by diarrhea
c. Explain the other lab results using the primary cause and
Equilibrium: CO2 + HOH === H2CO3 === H+ + HCO3-
If the bicarbonate is lower than normal, than the equilibrium
has shifted to the right, which increases hydrogen ions, and
decrease the pH.
d. State and explain how the compensation will return pH to
The table says that the compensation is for the lungs to blow
off carbon dioxide by hyperventilation. This means that the carbon
dioxide will be lower in the blood as a result. If carbon dioxide
is decreased, then the equilibrium shifts left, which decreases
the hydrogen ions, which increases the pH more toward normal.
e. Explain how the treatment with __?___ will work.
The suggested treatment is to give an IV with sodium bicarbonate.
If bicarbonate is increased, then the equilibrium shift left,
which decrease the hydrogen ion concentration, which increase
the pH more toward normal.